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Write a Shell Bash Script for check if a provided number is Armstrong or not
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| #!/usr/bin/env bash | |
| echo -n "Enter A Number: " | |
| read -r n | |
| arm=0 | |
| temp=$n | |
| while [ "$n" -ne 0 ]; do | |
| r=$((n % 10)) | |
| arm=$((arm + r * r * r)) | |
| n=$((n / 10)) | |
| done | |
| echo $arm | |
| if [ $arm -eq "$temp" ]; then | |
| echo "Armstrong" | |
| else | |
| echo "Not Armstrong" | |
| fi |
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#Your’s is wrong and works only for 3 digits but this one works flawlessly
#!/bin/bash
read -p “Enter Number:” num
temp=$num
arm=0
count=${#num}
if [ $num -lt 10 ]
then
echo “$num is armstrong number (1-9)”
else
while [ $num -gt 0 ]
do
rem=$((num%10))
arm=$((arm + rem**count))
num=$((num/10))
done
if [ $arm -eq $temp ]
then
echo “$arm = $temp Armstrong Number!”
else
echo “$arm != $temp Not a Armstrong Number!”
fi
fi